回复v2721672发表于:2020/5/11 10:37:57悬赏金额:
10积分 状态:
未解决
采用微波消解-火焰原子吸收测定面粉锌含量,数据如下:
标准曲线:0 ppm 0.0007(ABS)
0.2 ppm 0.0428(ABS)
0.4 ppm 0.0833(ABS)
0.6 ppm 0.1208(ABS)
0.8 ppm 0.1577(ABS)
1.0 ppm 0.1915(ABS)
R值:0.9993
试剂空白: 0.04 ppm 0.0109(ABS)
生物成分标准物质:0.07 ppm 0.0180(ABS)
样品:1、0.12ppm 0.0271(ABS)
2、0.14ppm 0.0304(ABS)
3、0.08ppm 0.0188(ABS)
4、0.14ppm 0.0299(ABS)
5、0.10ppm 0.0225(ABS)
6、0.14ppm 0.0302(ABS)
7、0.15ppm 0.0327(ABS)
8、0.13ppm 0.0294(ABS)
9、0.15ppm 0.0322(ABS)
10、0.11ppm 0.0250(ABS)
称样量是0.3g左右,最后定容到50ml.
计算得生物成分标准物质为5.14ppm,而给定值是2.9±0.3ppm。不知道问题出在哪里,急求大家指点讨论!